1) Draw The Free-body Diagram For The Supporting Side Truss Of The Bridge. Label And Indentify All Joints, And Indicate All Forces On Members. 2) What Are The Reaction Forces At The Pylons? 3) Find The Internal Forces In Each Truss Member (indicating If Is Is Compressive Or Tensile). 4) What Do You Notice In The Picture About The Compressive Vs. Tensile …

1) Draw The Free-body Diagram For The Supporting Side Truss Of The Bridge. 
Label And Indentify All Joints, And Indicate All Forces On Members. 2) What 
Are The Reaction Forces At The Pylons? 3) Find The Internal Forces In Each 
Truss Member (indicating If Is Is Compressive Or Tensile). 4) What Do You 
Notice In The Picture About The Compressive Vs. Tensile ...

Transcribed Text:
Question: 1) Draw the free-body diagram for the supporting side truss of t…
1) Draw the free-body diagram for the supporting side truss of the bridge. Label and indentify all joints, and indicate all forces on members. 2) What are the reaction forces at the pylons? 3) Find the internal forces in each truss member indicating if is is compressive or tensile).


— — – — — WWWWW
th an isolation of the entire structure:
ANA
Rs,
12
R
1 3 W
5 W
7 W
9 W
11 W
A
4) What do you notice in the picture about the compressive vs. tensile members? Are all the members the same size? Explain your answer. 5) What would happen if you remove the two circled truss members from the bridge? let alpha=1 Show transcribed image text View comments (1) ►
Expert Answer
Evan Kim answered this 3,367 answers
Was this answer helpful? B2
po
Draw the free body diagram of the truss.
DF
SO
Calculate the reactions at A and L. Take moment about A.
MA=0 L,(3a) – P(2.5a) – P(2a) – P(1.50) |-P(a) – P(0.5a) 31, -7.5P=0
L = 2.5P Resolve the forces along y-axis.
F, = 0 4, +L-10P=0 4, +2.5P-5P=0 4, = 2.5P
Resolve the forces along x-axis.
F = 0 A=0
Consider joint A.
Resolve the forces along y-axis.
F, = 0 4, +Fesin 45o = 0 2.5P+ FAR sin 45o = 0 FB = -3.54P
F. = 3.54P(C) Resolve the forces along x-axis.
EF, =0 FAB cos 45o +Fac=0 (-3.54) cos 45o + F = 0
Fin = 2.5P(T) Since, the members AC and CE are in collinear, thus F.c = Fce = 2.5P(T)
Consider joint C.
Resolve the forces along y-axis.
EF=0 Fgc – P=0
Fgc = P(T) Similarly, will get the all other forces in all members.

Leave a Reply

Your email address will not be published. Required fields are marked *