# Question: Draw all the structural isomers for the molecular formula C4H9Br. Be careful not to draw any structure –Free Chegg Question Answer

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Answer:

### Step 1 of 2

There are 4 carbon atoms, 9 hydrogen atoms and 1 bromine atom present in the molecular formula {{\rm{C}}_{\rm{4}}}{{\rm{H}}_{\rm{9}}}{\rm{Br}}C4​H9​Br .

There are two possible carbon chains which are having 4 carbon atoms as given below:

Explanation | Common mistakes | Hint for next step

The two structures were drawn based on the given molecular formula in which there are four carbon atoms present.

### Step 2 of 2

I. 4-membered longest carbon chain:

1.1-bromobutane

2.2-bromobutane

II. 3-membered longest carbon chain with methyl substituent.

3.1-bromo-2-methylpropane

4.2-bromo-2-methylpropane

The possible structural isomers for {{\rm{C}}_{\rm{4}}}{{\rm{H}}_{\rm{9}}}{\rm{Br}}C4​H9​Br are as follows:

Explanation | Common mistakes

In four membered longest carbon chain, bromine substituted at two different types of carbons leads to primary and secondary bromide structures. In three membered longest carbon chain with methyl substituent, bromine substituted at two different types of carbons leads to primary and tertiary bromide structures. There are four possible isomers for given molecular formula {{\rm{C}}_{\rm{4}}}{{\rm{H}}_{\rm{9}}}{\rm{Br}}C4​H9​Br .

1.1-bromobutane

2.2-bromobutane

3.1-bromo-2-methylpropane

4.2-bromo-2-methylpropane