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Question: Draw the Fischer projection for the D-2-ketotetrose. Switch between an aldose and a ketose by clicking on “switch carbonyl group.” Add or delete carbon atoms using the add (” “) or delete (“x”) buttons. Clicking on a blue box once adds a hydrogen atom (H). Clicking on a blue box again toggles between H and OH.– Free Chegg Question Answer

Draw the Fischer projection for the D-2-ketotetrose. Switch between an aldose and a ketose by clicking on “switch carbonyl group.” Add or delete carbon atoms using the add (” “) or delete (“x”) buttons. Clicking on a blue box once adds a hydrogen atom (H). Clicking on a blue box again toggles between H and OH.

Transcribed text From Image: 1) Find the area of the indicated region under the standard normal curve. -1 30 0 - 1300 -0.45 2 .11 -1.130 2.03 2) Find the area under the standard normal curve to the left of 2 - 1.25 3) Find the area under the standard normal curve to the right of z = 1. 4) Find the area under the standard normal curve between 2 = 0 and 2 = 3. 5) Find the area under the standard normal curve between 2 = -1.25 and 2 -1.25. 6) Find the sum of the areas under the standard normal curve to the left of 2 = -1.25 and to the right of 1.25 7) Use the standard normal distribution to find Piz 1.53). 11) Use the standard normal distribution to find P(-2.25

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Answer:

Answer


General guidance

Concepts and reason

The structure of a ketotetrose needs to be drawn. The name denotes that the molecule belongs to carbohydrate family. Hence, draw the structure by considering the rules for drawing a carbohydrate. Fundamentals

To deduce the structure of carbohydrate, follow the steps given below:

• Determine the group that the carbohydrate belongs to from the name like monosaccharides (consists of one unit), disaccharides (two units of monosaccharides), or oligosaccharides (3-8 units of monosaccharides).

For example: aldotriose is a monosaccharide, maltose is a disaccharide which gives two molecules of glucose on hydrolysis and so on.

• Draw the chain containing total number of carbons from the given number. For example: triose represent a 3-carbon chain and so on.

• Deduce whether the molecule is an aldehyde or ketone. For example: aldo represent an aldehyde and keto represent a ketone to get the complete structure.

• The D and L nomenclature configuration decides the position of the OH group bonded to the last chiral carbon. Show more First Step | All Steps | Answer Only

Step-by-step

Step 1 of 3

The given molecule is a monosaccharide.Explanation

The molecule is a monosaccharide because tetrose represent a single molecule consisting of four-carbons.

Step 2 of 3

The molecular formula of the given molecule is C4H8O4{{
m{C}}_4}{{
m{H}}_8}{{
m{O}}_4}C4​H8​O4​ Explanation

The molecule is a monosaccharide which have the general formula (CnH2nOn)left( {{{
m{C}}_n}{{
m{H}}_{2n}}{{
m{O}}_n}}
ight)(Cn​H2n​On​) . The molecule is a Tetrose that is containing four carbon atoms. Substitute n=4{
m{n}};{
m{ = }};{
m{4}}n=4 in the general formula. Therefore, the molecular formula of the given molecule is C4H8O4{{
m{C}}_4}{{
m{H}}_8}{{
m{O}}_4}C4​H8​O4​ .

Step 3 of 3

The structure of the D-2-ketotetrose is as follows:

CH-OH
-ОН
CH OH

The structure of the D-2-ketotetrose is as follows:

CH-OH
-ОН
CH OH

Explanation

The molecule is a ketose. Hence, it has a ketone moiety present. The general structure of a ketose is as shown below:

Therefore, draw a four-carbon chain and attach a ketone moiety at the second position.

Since, the molecule has D-configuration, therefore, the OH attached on the last chiral carbon is present on the right side. C1, C3 and C4 contain OH groups.

Therefore, the structure of the molecule satisfying the molecular formula C4H8O4{{
m{C}}_4}{{
m{H}}_8}{{
m{O}}_4}C4​H8​O4​ is as shown below:

Answer

The structure of the D-2-ketotetrose is as follows:

CH-OH
-ОН
CH OH

Answer only

The structure of the D-2-ketotetrose is as follows:

CH-OH
-ОН
CH OH

CH-OH -ОН CH OH CH,OH FO (CHOH) CH,OH 1CH,OH 2 PO OH OH present to the right) 4 CH OH (chiral carbon) CH-OH -ОН CH OH CH-OH -ОН CH OH

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