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Question: A large rock is released from rest from the top of a tall building. The average speed of the rock during the first second of the fall is 5 m/s. What is the average speed of the rock during the next second? – Free Chegg Question Answer

A large rock is released from rest from the top of a tall building. The average speed of the rock during the first second of the fall is 5 m/s. What is the average speed of the rock during the next second?

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Take the case of first second.
Inital velocity, u = 0m/s (since the rock is dropped)
Final velocity = v m/s.
Average velocity = (u+v)/2 = 5 m/s.
From this, v = 10 m/s.

Next second.
Initial velocity u = 10 m/s.
Final velocity, v = u + gt.
Here g = 9.8 m/s2, t = 1 s.
v = (10 + 9.8 x 1) = 19.8 m/s.
Average velocity = (u+v)/2 = 14.9 m/s.


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