# Consider The Diagram Below That Shows A Water Pump Used To Move Water From One Large Reservoir To Another At A Higher Elevation. The Pump’s Performance Is Approximated By The Expression Havialable = H0 – A∙Q2 Where H0 Is 24.4m Of Water And A Is 0.0678m/Lpm2, Havailable Is In Units Of Meters And Capacity, Q, Is In Units Of Lpm (Note: Lpm = Liters …

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Question: Consider the diagram below that shows a water pump used to …
(1 bookmark) Consider the diagram below that shows a water pump used to move water from one large reservoir to another at a higher elevation. The pump’s performance is approximated by the expression Havialable = Ho-a-Q2 where Ho is 24.4m of water and a is 0.0678m/Lpm?, Havailable is in units of meters and capacity, Q, is in units of Lpm (Note: Lpm = liters per minute). Estimate the capacity delivered by the pump in this system (give your answer in Lpm).
22-2y = 7.85 m (elevation difference)
D = 2.03 cm (pipe diameter) KL, entrance = 0.50 (pipe entrance) KL. valve = 17.5 (valve) KL elbow = 0.92 (each elbow-there are 5) KL. exit = 1.05 (pipe exit)
L = 176.5 m (total pipe length) E = 0.25 mm (pipe roughness)
Reservoir
22-21
Dv, = 0
Reservoir
Pump
Valve
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350
we apply the energy equation in head form between the iniet reservoir’s free surface (1) and ou that (2)
– P2-P, da ve 2 – 2, 0,2 .. ut Hrequired pump –
29 hturbine the totalt
+(Z2-Z,)+
09
Since both free Surfaces are al atmospheric pressure 1. P, = P2 = Patm. There is no flow , V = U2=0. There is
no turbine. hturb=0
.: +requined =
=
(-2,-2
) +h
t
teu
= 2; -7:) + [4 5 +EKT
(2)
The
dimensionless, roughness
factor,
0.25 (mm) 2.03 (cm) .
0.0123

The
sum
of all minor loss coefficients EK -0.5+17.5+ (5×0.92)+105
23.65
The
pump
system operates at Conditions where Havailable = Hrequired
os toca no tengo 2 = (3,-2)*(*\$*\$k]
where v = v 702
. Le
Equation (3) is implicit equālion for v since Dorey friction factor f is function of Reynolds no.
Re= PVD
The
solution is obtained by iterative method
V=0.596033 0.596
:: j = 11.6 Lpm
{re = 1.218104}