# Consider The Diagram Below That Shows A Water Pump Used To Move Water From One Large Reservoir To Another At A Higher Elevation. The Pump’s Performance Is Approximated By The Expression Havialable = H0 – A∙Q2 Where H0 Is 24.4m Of Water And A Is 0.0678m/Lpm2, Havailable Is In Units Of Meters And Capacity, Q, Is In Units Of Lpm (Note: Lpm = Liters …

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Question: Consider the diagram below that shows a water pump used to …

(1 bookmark) Consider the diagram below that shows a water pump used to move water from one large reservoir to another at a higher elevation. The pump’s performance is approximated by the expression Havialable = Ho-a-Q2 where Ho is 24.4m of water and a is 0.0678m/Lpm?, Havailable is in units of meters and capacity, Q, is in units of Lpm (Note: Lpm = liters per minute). Estimate the capacity delivered by the pump in this system (give your answer in Lpm).

22-2y = 7.85 m (elevation difference)

D = 2.03 cm (pipe diameter) KL, entrance = 0.50 (pipe entrance) KL. valve = 17.5 (valve) KL elbow = 0.92 (each elbow-there are 5) KL. exit = 1.05 (pipe exit)

L = 176.5 m (total pipe length) E = 0.25 mm (pipe roughness)

Reservoir

22-21

Dv, = 0

Reservoir

Pump

Valve

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we apply the energy equation in head form between the iniet reservoir’s free surface (1) and ou that (2)

– P2-P, da ve 2 – 2, 0,2 .. ut Hrequired pump –

29 hturbine the totalt

+(Z2-Z,)+

09

Since both free Surfaces are al atmospheric pressure 1. P, = P2 = Patm. There is no flow , V = U2=0. There is

no turbine. hturb=0

.: +requined =

=

(-2,-2

) +h

t

teu

= 2; -7:) + [4 5 +EKT

(2)

The

dimensionless, roughness

factor,

0.25 (mm) 2.03 (cm) .

0.0123

”

The

sum

of all minor loss coefficients EK -0.5+17.5+ (5×0.92)+105

23.65

The

pump

system operates at Conditions where Havailable = Hrequired

os toca no tengo 2 = (3,-2)*(*$*$k]

where v = v 702

. Le

Equation (3) is implicit equālion for v since Dorey friction factor f is function of Reynolds no.

Re= PVD

The

solution is obtained by iterative method

V=0.596033 0.596

:: j = 11.6 Lpm

{re = 1.218104}