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Question: Draw a Lewis dot structure for TeF4 with any lone pairs

Draw a Lewis dot structure for TeF4 with any lone pairs

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Answer:

Answer 1:

Answer 2:

Answer 3:

Step 1: Find valence e- for all atoms. Add them together.

Te:6
F-7×4=28

Total=34

Step2: Find octet e- for each atom and add them together.

Te-10*
F-8×4=32

Total=42

*Te gets expanded octet to facilitate the formation of 4 bonds with surrounding atoms.

Step3: Gives you bonding e-. Subtract step 1 total from step 2

42-34=8e-

Step 4: Find number of bonds by diving the number in step 3 by 2(because each bond is made of 2 e-)

8e-/2= 4 bond pairs

Step 5: Find the number of nonbonding (lone pairs) e-. Subtract step 3 number from step 1.

34-8= 26e-=13 lone pairs

Use information from step 4 and 5 to draw the lewis structure.


Lewis dot structure of Tef4

Alternatively a dot method can be used to draw the lewis structure.
Calculate the total valence electrons in the molecule.
Te:6
F-7×4=28

Total=34

Put Tellurium in center and arrange fluorine atoms on the sides.Arrange electrons until fluorine atoms get 8 electrons.( Tellurium gets 10 electrons, which is an expanded octet)

Answer 4:

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