# Question: Calculus (6th Edition) –Free Chegg Question Answer

Calculus (6th Edition)

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### Step-by-step solution

- Step 1 of 4
**Concept:**Suppose a function in two variables. The partial derivative represents the derivative of function w.r.t. provided is taken to be a constant i.e. Further, the notation means differentiation of the function w.r.t. and then w.r.t. provided other variables are taken to be constant. i.e. Comment - Step 2 of 4 The objective here is to show that and for all , and then show that and where According to the above concept, Simplify the above derivative. Now, differentiate w.r.t. taking as constant. Find at Similarly, find Comment
- Step 3 of 4 Now, differentiate w.r.t. taking as constant. Find at Now, find and by differentiating and respectively taking other variable constant. Thus, at Similarly, find at Comment
- Step 4 of 4 Therefore, and , and hence and