Draw The Major Organic Product Formed In The Following Reaction. Ch3 Conc. H H3C____|_____ch___ch3 —-> ? | | ? Ch3 OH

Draw The Major Organic Product Formed In The Following Reaction. Ch3 Conc. 
H H3C____|_____ch___ch3 ----> ? | | ? Ch3 OH” width=”100%”  /></p>
<p><strong>Transcribed Text:</strong><br />
Question: Draw the major organic product formed in the following &nb…<br />
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Draw the major organic product formed in the following reaction.<br />
h3C_<br />
ch3<br />
conc. H I____ch__ch3 —-><br />
?<br />
ch3<br />
OH<br />
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Expert Answer<br />
Was this answer helpful? B2<br />
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General guidance<br />
Concepts and reason Alcohols undergo a dehydration reaction when the react with concentrated acids in the presence of heat. Product formation is undergone with the help of an elimination reaction.<br />
Fundamentals When alcohols undergo a reaction with strong acids (like H2SO4, H3PO4) in the presence of heat, it forms an alkene product with the elimination of water. It undergoes 1, 2 -elimination to form an alkene. Example:<br />
Con.H*<br />
H2C= CH2 + H2O<br />
H.C—<br />
—OH<br />
Show less<br />
Step-by-step<br />
FIRST STEP ALL STEPS | ANSWER ONLY<br />
Step 1 of 2 ^<br />
H30—¢-CH3 —<br />
+<br />
– CH2 Học-–&— –CH3<br />
CH, POH?<br />
+ HỌCoca<br />
-CH,<br />
CH3 : OH<br />
Lh<br />
Hö:<br />
Explanation Common mistakes Hint for next step<br />
The alcoholic oxygen undergoes protonation with the help of a lone pair of electrons and makes it a better leaving group. Then the leaving group cleaves and forms a carbocation intermediate which is the rate determining step for this reaction.<br />
Step 2 of 2 ^<br />
Hö:<br />
– CH2 ķ HC—’¢CH3 —<br />
H3C<br />
H3C—<br />
—<br />
—CH3 —<br />
CHz<br />
HzĆ<br />
H30+<br />
CH3<br />
H3C<br />
CH3<br />
H3C-¢-CH,<br />
Con. Ht<br />
+<br />
H2O<br />
CH3 OH<br />
H3C<br />
CH3<br />
Explanation Common mistakes<br />
The methyl group is rearranged and forms carbocation in the second carbon. Then the lone pair of oxygen electrons abstracts a proton and forms an alkene product by stabilizing the carbocation.<br />
Answer<br />
CH3<br />
H3C<br />
Con. H+<br />
H2C-<br />
C<br />
+<br />
H2O<br />
CH3 OH<br />
H3C<br />
CH2</p><div class='code-block code-block-3' style='margin: 8px auto; text-align: center; display: block; clear: both;'>
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