Draw The Product(s) Of The Following Reactions.

Draw The Product(s) Of The Following Reactions.

Transcribed Text:
Question: Draw the product(s) of the following reactions.
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Draw the product(s) of the following reactions.
1. BH3 / THE
(CH3)2CHCH2-CEC-CH2CH3
2. H2O2 / aqueous NaOH
• You do not have to consider stereochemistry. • Separate multiple products using the + sign from the dropdown menu. • You do not have to explicitly draw H atoms. • If no reaction occurs, draw the starting material.
-CEC-CH3
Pd/C
Na/NH3(0)
CH3CH2CH2CH2-CEC-CH2CH2CH2CH3
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Isaac Subramanium 276 answers
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Internal alkyne on hydroboration-oxidation forms ketone over the carbon which is less substituted in accordance to Anti-Markownikoff’s rule, but when the internal alkyne has equally substituted carbon at carbon-carbon triple bond, then the ketone group can be formed on either side of the bond.
Here, the internal alkyne is. The products formed is as follows:
I-
(H3C),HCH,C—C=C—CH.CH
1. BH/THF
(H3C),HCH2C- 2.H2O2/aqueous NaOH
C
CH2CH3
6-methylheptan-3-one
(H2C) HCHC—
C—
C—
CH CH3
2-methylheptan-4-one The treatment of prop-1-yn-1-ylbenzene with H, in the presence of Pd/Carbon eliminates the unsaturation due to this hydrogenation. The product obtained is as follows:
H2
-EC-CH3
PdC
prop-1-yn-1-ylbenzene
propylbenzene
The treatment of the alkyne, dec-5-yne with the reducing agent Na/NH, to form trans alkene. The product obtained is as follows:
H3CH2CH2CH2C
Na NH /
H3CH2CH2CH2C—
=
C= C—CH2CH2CH2CH3 – dec-5-yne
CH2CH2CH2CH3 dec-5-ene (trans product)

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