# Question: Find the exact length of the curve. y^2 = 64(x + 4)^3, 0 lessthanorequalto x lessthanorequalto 2, y > 0 For a curve given by y = f(x), arc length is given by: We have y^2 = 64(x + 4)^3, y > 0 which can be re-written as follows. Now, dy/dx = 12(x + 4)^(1/2) The arc length can be found by the integral: L = integral^2_0 dx.

**Find the exact length of the curve. y^2 = 64(x + 4)^3, 0 lessthanorequalto x lessthanorequalto 2, y > 0 For a curve given by y = f(x), arc length is given by: We have y^2 = 64(x + 4)^3, y > 0 which can be re-written as follows. Now, dy/dx = 12(x + 4)^(1/2) The arc length can be found by the integral: L = integral^2_0 dx.**

Transcribed text: This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise Find the exact length of the curve. y2 = 64(x + 4)3, OSXS 2, > 0 Step 1 For a curve given by y = f(x), arc length is given by: L76 Step 2 We have y2 = 64(x + 4)3, y > which can be re-written as follows. v= B28) (x + 4,322 32 Step 3 Now, 12(x + 4) () 12 (+2547 Step 4 The arc length can be found by the integral: L=6 + Submit Skip (you cannot come back)

## Expert Chegg Question Answer:

Answer:

Faq:***