# Question: Find the exact length of the curve. y^2 = 64(x + 4)^3, 0 lessthanorequalto x lessthanorequalto 2, y > 0 For a curve given by y = f(x), arc length is given by: We have y^2 = 64(x + 4)^3, y > 0 which can be re-written as follows. Now, dy/dx = 12(x + 4)^(1/2) The arc length can be found by the integral: L = integral^2_0 dx.

Find the exact length of the curve. y^2 = 64(x + 4)^3, 0 lessthanorequalto x lessthanorequalto 2, y > 0 For a curve given by y = f(x), arc length is given by: We have y^2 = 64(x + 4)^3, y > 0 which can be re-written as follows. Now, dy/dx = 12(x + 4)^(1/2) The arc length can be found by the integral: L = integral^2_0 dx.

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Tutorial Exercise
Find the exact length of the curve.
y2 = 64(x + 4)3, OSXS 2, > 0
Step 1
For a curve given by y = f(x), arc length is given by:
L76
Step 2
We have y2 = 64(x + 4)3, y > which can be re-written as follows.
v= B28) (x + 4,322 32
Step 3
Now,
12(x + 4) ()
12 (+2547
Step 4
The arc length can be found by the integral:
L=6
+
Submit
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