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Question: Find the exact length of the curve. y^2 = 64(x + 4)^3, 0 lessthanorequalto x lessthanorequalto 2, y > 0 For a curve given by y = f(x), arc length is given by: We have y^2 = 64(x + 4)^3, y > 0 which can be re-written as follows. Now, dy/dx = 12(x + 4)^(1/2) The arc length can be found by the integral: L = integral^2_0 dx.

Transcribed text From Image: Find the exact length of the curve. y^2 = 64(x + 4)^3, 0 lessthanorequalto x lessthanorequalto 2, y > 0 For a curve given by y = f(x), arc length is given by: We have y^2 = 64(x + 4)^3, y > 0 which can be re-written as follows. Now, dy/dx = 12(x + 4)^(1/2) The arc length can be found by the integral: L = integral^2_0 dx.

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