Inside Of The Tank Shown In The Schematic, Water Is Pressurized By A Compressed Gas On Top Of The Water. The Pressure Of The Gas Is Measured Using A U-tube Manometer Which Has A Gage Fluid With A SG Of 7. At The Bottom Of The Water Tank (1.5 M Below The Surface Of The Water) A Valve With An Inside Diameter Of 2 Cm Is Opened To The Atmosphere. If The …

Inside Of The Tank Shown In The Schematic, Water Is Pressurized By A 
Compressed Gas On Top Of The Water. The Pressure Of The Gas Is Measured 
Using A U-tube Manometer Which Has A Gage Fluid With A SG Of 7. At The 
Bottom Of The Water Tank (1.5 M Below The Surface Of The Water) A Valve 
With An Inside Diameter Of 2 Cm Is Opened To The Atmosphere. If The ...

Transcribed Text:
Question: Inside of the tank shown in the schematic, water is pressurized …
Inside of the tank shown in the schematic, water is pressurized by a compressed gas on top of the water. The pressure of the gas is measured using a U-tube manometer which has a gage fluid with a SG of 7. At the bottom of the water tank (1.5 m below the surface of the water) a valve with an inside diameter of 2 cm is opened to the atmosphere. If the height difference between the gage fluid surfaces in the U-tube is 7.5 cm, determine a) the velocity of the water leaving the valve and b) the mass flow rate of the water leaving the system.
7.5 cm
SG = 7
1.5 m
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RustyFrog9812 answered this 1,233 answers
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Mate
Pressure at bottom of tanks
e at bottom of tank xlopex 9.&IX0-075
+ 1000×98 X 1.5 P = 19950.25 Pa -P2 = 0 Pa (Atmospheric) (shown as Datum)
v=0ms ( statimory) Applying Bouncullis principle blo 4*2we get
V2 = 19890.25 ..
1000 x 9.81
V2 = 2x 19850.25
Velocity at V2 = 6.301 m/s Ans. outlet of valves Diameton, Da2cm = 0.02 Moss flono note, m px A x DŽENO
– loto x T X0:02 x 6:30) = 1.985 kg/s Aus

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