Question: Predict the major product for the following reaction. When draw…
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Predict the major product for the following reacton.
Predict the major product for the following reaction When drawing hydrogen atoms on a carbon atom, either include all hydrogen atoms or none on that carbon atom, or your structure may be marked incorrect.
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Solution Video Bipo 04:12
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Concepts and reason Alkenes contain unsaturated double bonds, which undergo electrophilic addition reactions. In addition reactions, the weaker pi bond in an alkene breaks into two new stronger sigma bonds. Addition reactions are regioselective based on the reagent used. In the presence of peroxide, addition of alkyl halide to asymmetric alkene gives anti Markovnikov’s product.
FIRST STEP ALL STEPS ANSWER ONLY
Step 1 of 3 ^
Draw the mechanism for the initiation step of the reaction as show below: R-03-0-R – 2R-0
R-O + HLBr
Explanation Common mistakes Hint for next step Free radicals are produced by the cleavage of oxygen-oxygen bond in the peroxide. This free radical abstracts the hydrogen atom from a hydrogen bromide molecule to produce bromine radical.
Step 2 of 3 ^
Draw the mechanism for the propagation step of the reaction as shown below:
Explanation Common mistakes Hint for next step Bromine radical formed in the above step is added to the alkene by using one electron in the n bond and forms a new radical on alkyl. This step is called the chain propagation reaction. Radical is the reaction intermediate in this reaction so there is always a tendency that a most stable radical is formed and on chain propagation step radical is continuously regenerating.
Step 3 of 3 ^
Draw the mechanism for the termination step of the reaction as shown below: Br
Thus, the major product of the reaction is shown below:
The alkyl radical formed in the above step react with the other HBr molecules to produce alkyl bromide. In this reaction, alkyl halide is formed through homolytic cleavage of hydrogen halide bond and bromine radical is regenerated which eventually combines with another radical and the reaction terminates at this stage.
Answer Thus, the major product of the reaction is shown below: