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Question: “PART A What Property Of Objects Is Best Measured By Their Capacitance? A)ability To Conduct Electric Current B)ability To Distort An External Electrostatic Field C)ability To Store Charge Part B Assume That Charge ?q Is Placed On The Top Plate, And +q Is Placed On The Bottom Plate. What Is The Magnitude Of The Electric Field E Between The Plates? Express …”

“PART A What Property Of Objects Is Best Measured By Their Capacitance? A)ability To Conduct Electric Current B)ability To Distort An External Electrostatic Field C)ability To Store Charge Part B Assume That Charge ?q Is Placed On The Top Plate, And +q Is Placed On The Bottom Plate. What Is The Magnitude Of The Electric Field E Between The Plates? Express …”

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Question: PART A What property of objects is best measured by their capa…
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PARTA What property of objects is best measured by their capacitance?
a)ability to conduct electric current
b)ability to distort an external electrostatic field
c)ability to store charge Part B Assume that charge ?g is placed on the top plate, and +g is placed on the bottom plate. What is the magnitude of the electric field E between the plates? Express Ein terms of q and other quantities given in the introduction, in addition to 20 and any other constants needed.
E=
Part What is the voltage V between the plates of the capacitor? Express Vin terms of the quantities given in the introduction and any required physical constants. Part D Now find the capacitance C of the parallel-plate capacitor. Express Cin terms of quantities given in the introduction and constants like 20. Part E Consider an air-filled charged capacitor. How can its capacitance be increased? Consider an air-filled charged capacitor. How can its capacitance be increased?
Increase the charge on the capacitor.
Decrease the charge on the capacitor.
Increase the spacing between the plates of the capacitor.
Decrease the spacing between the plates of the capacitor.
Increase the length of the wires leading to the capacitor plates. Part F Consider a charged parallel-plate capacitor. Which combination of changes would quadruple its capacitance? Consider a charged parallel-plate capacitor. Which combination of changes would quadruple its capacitance?
Double the charge and double the plate area.
Double the charge and double the plate separation.
Halve the charge and double the plate separation.
Halve the charge and double the plate area.
Halve the plate separation; double the plate area.
Double the plate separation; halve the plate area.
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Solution Video B 13 po 04:16
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anil.roy answered this 753 answers
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PartA; C) ability to store charge.
Part B); E = Q/EA; where A is the area of the plates.
Part C: V = E / d. Part D; C = € A/d.
Part E; decrease the spacing between the plates of the capacitor.
Part F; halve the plate separation; double the plate area.
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