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Question: Report on Laboratory Experiment “Acceleration Laboratory Experiment “Acceleration Due to Gravity: Free Fall Apparatus” DATA TABLE First height data Second height data Third height data Height h (m) 10.90 10.65 10.40 Trial 1 10.4526 10.3748 10.3330 Trial 2 10.4344 0.3748 0.2795 Time t(s) Trial 3 6. 3748 0.3103 Trial 4 0.4608 (6.4383 16.4489 16.3714 10.2843 Trial 5 0.3740 0.3245 Average time t (s) 10.445 0.300 32 10.37396 1.31.138 72.98 1.81.2070 8.69 Calculated value of g (m/s2) .81043 8.602 Average value of the gravitational acceleration g (m/s2) % Error of 8 Please show here the calculation – Free Chegg Question Answer

What’s % error of g?

Report on Laboratory Experiment Acceleration Laboratory Experiment Acceleration Due to Gravity: Free Fall Apparatus DATA T
Transcribed text From Image: Report on Laboratory Experiment "Acceleration Laboratory Experiment "Acceleration Due to Gravity: Free Fall Apparatus" DATA TABLE First height data Second height data Third height data Height h (m) 10.90 10.65 10.40 Trial 1 10.4526 10.3748 10.3330 Trial 2 10.4344 0.3748 0.2795 Time t(s) Trial 3 6. 3748 0.3103 Trial 4 0.4608 (6.4383 16.4489 16.3714 10.2843 Trial 5 0.3740 0.3245 Average time t (s) 10.445 0.300 32 10.37396 1.31.138 72.98 1.81.2070 8.69 Calculated value of g (m/s2) .81043 8.602 Average value of the gravitational acceleration g (m/s2) % Error of 8 Please show here the calculation

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Obtained avg value of g from the trials = 8.865 m/s2

Actual value of g = 9.8 m/s2

So, the % error = ((9.8 – 8.865) / 9.8) x 100 % = 9.54 %

Hence the error % is 9.54 %


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