|

Question: Write the IUPAC names of the following carboxylic acids.

Write the IUPAC names of the following carboxylic acids…………..

Transcribed text From Image: Write the IUPAC names of the following carboxylic acids.

Expert Chegg Question Answer:

free chegg question answer
Smart Teacher From Answerie.com
Answer:

Answer


General guidance

Concepts and reason

IUPAC stands for the international union of pure and applied chemistry. IUPAC nomenclature is a standardized method for naming the organic compounds. IUPAC name consists of four parts; root word, suffix, prefix. The structure of the compound can be drawn easily by analysing these parts i.e. root word, suffix, prefix and infix. Fundamentals

IUPAC name consists of three parts namely, Prefix, root name and suffix.

The prefix is the substituent (usually an alkyl group) attached to a carbon atom of longest chain.

Root name represents the longest carbon skeleton in a molecule.

Suffix indicates the presence of functional groups if any (Example: ane is used for alkane, ene is used for alkene, yne is used for alkyne)

A functional group like CHO, COOH, OH etc.… (al, oic acid and ol) in the molecule should be used as a suffix.

Infix is used for cyclic compounds. Example: a single ring is represented as cyclic; a double ring is represented as bicyclic. Show less First Step | All Steps | Answer Only

Step-by-step

Step 1 of 6

Part a

оснз
На
Н2
С
Hас-
-С—ОН
-С
1
2

Root name: pentExplanation | Common mistakes | Hint for next step

In the given compound, the long chain consists of five carbons and the numbering starts from the carbon that present in functional group. Therefore, the root name is pent.

Take care while numbering the functional group carbon which should be less in number.

Example:

Correct:

Wrong:

Find the substituents present in the given structure.

Step 2 of 6

(ОСН3,
На
C
5
Н2
С
Нас —с
С
-С— он
1
4
2
3

Prefix: 3 – methoxyExplanation | Common mistakes | Hint for next step

In the given compound, only one substituent is present in the third carbon. The substituent contain methyl group attached to oxygen which is represented as methoxy. Therefore, the prefix of the given compound is 3 – methoxy.

When writing prefix, do not forget to mention the substituent attached to carbon number.

Correct:

Prefix: 3 – methoxy

Wrong:

Prefix: methoxy

Find the suffix present in the given structure.

Step 3 of 6

о
ОСHЗ
Н2
-с +с—
Н2
Hас — с
C
-OH
н

Suffix: oic acid.

Part aPart a

The name is as follows:

оснз
Н2
Hас — с
Н2
-с-
-С—он
-от

IUPAC Name: 3 – methoxypentanoic acid.
Explanation | Common mistakes | Hint for next step

The suffix represents the functional group. In this given structure, carboxylic acid (−COOH){\rm{( – COOH)}}(−COOH) is a functional group. Hence, for carboxylic acid group (oic acid) is a suffix.

Take care while writing the names of the organic compound. The order should not be changed. It should be written as: prefix, Root name and suffix.

Correct:

IUPAC Name: 3 – methoxypentanoic acid.

Wrong:

IUPAC Name: pentane 3 – methoxy acid.

Identify the long carbon chain from the given structure.

Step 4 of 6

Part b

С—ОН
1
6
2
3
5
4

Root name: BenzeneExplanation | Common mistakes | Hint for next step

The given compound is in the shape of a aromatic ring that contains 6 carbons. The 6 – carbon cyclic ring is represented as Benzene which is a root name for this compound.

Do not be confused with linear and ring compounds. Due to 6 carbons, it should not represented as hexane. The ring should be noticed.

Correct:

Root name: Benzene

Wrong:

Root name: hexane

Find the substituents in the given compound.

Step 5 of 6

Cㅡ-OH
6
2
5
4

Prefix: 4-ChloroExplanation | Common mistakes | Hint for next step

The given ring contains only one substituent in the 4th position. The substituent is chlorine and the prefix of the compound is 4 – chloro.

Do not forget to mention the numbering of the substituent. The numbering represents the position of substituent.

Correct:

Prefix: 4-Chloro

Wrong:

Prefix: Chloro

Find the suffix from the given compound.

Step 6 of 6

Suffix: oic acid.Part b

The name is as follows:

С— ОН
1
6
2
5
3
4
-о

IUPAC Name: 4 – chlorobenzoic acid.
Explanation | Common mistakes

The suffix represents the functional group. In this given structure, carboxylic acid (−COOH){\rm{( – COOH)}}(−COOH) is a functional group. Hence, for carboxylic acid group (oic acid) is a suffix.

Do not be confused with the substituent and functional group. The carboxylic acid in the ring is not taken as substituent. It is taken as suffix.

Correct:

Prefix: 4-Chloro

Wrong:

Prefix: 4-Chloro, 1-carboxylic acid.

Answer

Part a

The name is as follows:

оснз
Н2
Hас — с
Н2
-с-
-С—он
-от

IUPAC Name: 3 – methoxypentanoic acid. Part b

The name is as follows:

С— ОН
1
6
2
5
3
4
-о

IUPAC Name: 4 – chlorobenzoic acid.

Answer only

Part a

The name is as follows:

оснз
Н2
Hас — с
Н2
-с-
-С—он
-от

IUPAC Name: 3 – methoxypentanoic acid. Part b

The name is as follows:

С— ОН
1
6
2
5
3
4
-о

IUPAC Name: 4 – chlorobenzoic acid. оснз На Н2 С Hас- -С—ОН -С 1 2 оснз На Н2 С Hас- -С—ОН -С 1 2 оснз Н2 Hас- -с- -С—ОН Нас — с 1 2 5 4 (ОСН3, На C 5 Н2 С Нас —с С -С— он 1 4 2 3 оснз На Н2 С Hас- -С—ОН -С 1 2 оснз На Н2 С Hас- -С—ОН -С 1 2 о ОСHЗ Н2 -с +с— Н2 Hас — с C -OH н оснз Н2 Hас — с Н2 -с- -С—он -от оснз Н2 Hас — с Н2 -с- -С—он -от С—ОН 1 6 2 3 5 4 С—ОН 1 6 2 3 5 4 С—ОН 1 6 2 3 5 4 Cㅡ-OH 6 2 5 4 с —ОН 6 2 5 3 4 CI с —ОН 6 2 5 3 4 CI С—ОН 1 6 2 3 5 4 с —ОН 6 2 5 3 4 CI с —ОН 6 2 5 3 4 CI оснз Н2 Hас — с Н2 -с- -С—он -от оснз Н2 Hас — с Н2 -с- -С—он -от оснз Н2 Hас — с Н2 -с- -С—он -от оснз Н2 Hас — с Н2 -с- -С—он -от


Free Chegg Question Answer

Leave a Reply

Your email address will not be published. Required fields are marked *