| |

Question: A 2.00-kg mass oscillates on the end of a spring with spring constant 12.0 N/m. Its amplitude of oscillation decreases from 10.0 cm to 1.0 cm in 4.00 minutes. What is the linear damping coefficient of this oscillator? The answer is 0.0384 Ns/m please show how to get it – Free Chegg Question Answer

A 2.00-kg mass oscillates on the end of a spring with spring constant 12.0 N/m. Its amplitude of oscillation decreases from 10.0 cm to 1.0 cm in 4.00 minutes. What is the linear damping coefficient of this oscillator? The answer is 0.0384 Ns/m please show how to get it

Transcribed text From Image: 

Expert Chegg Question Answer:

free chegg question answer
Smart Teacher From Answerie.com
Answer:

Answer


Ao = 10 cm

A = 1 cm

m = 2 kg

t = 4 min = 4 x 60 = 240 sec

A = Ao e-bt/2m

1 = 10 e-240b/(2 x 2)

b = 0.0384


Free Chegg Question Answer

Leave a Reply

Your email address will not be published. Required fields are marked *